Difference between revisions of "Z80 Routines:Other:DispA"
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ld b, 0 ; B will count character length of number | ld b, 0 ; B will count character length of number | ||
- ld a, 10 | - ld a, 10 | ||
− | + | syscall DivHLByA ; HL = HL / A, A = remainder | |
push af | push af | ||
inc b | inc b |
Revision as of 14:39, 4 April 2005
; ITOA ; -------------------------------------------------------------- ; Converts a signed integer value to a zero-terminated ASCII ; string representative of that value (using radix 10). ; -------------------------------------------------------------- ; INPUTS: ; HL Value to convert (two's complement integer). ; DE Base address of string destination. (pointer). ; -------------------------------------------------------------- ; OUTPUTS: ; None ; -------------------------------------------------------------- ; REGISTERS/MEMORY DESTROYED ; AF HL ; -------------------------------------------------------------- itoa: push de push bc ; Detect sign of HL. bit 7, h jr z, _DoConvert ; HL is negative. Output '-' to string and negate HL. ld a, '-' ld (de), a inc de ; Negate HL (using two's complement) xor a sub l ld l, a ld a, 0 ; Note that XOR A or SUB A would disturb CF sbc a, h ld h, a ; Convert HL to digit characters _DoConvert: ld b, 0 ; B will count character length of number - ld a, 10 syscall DivHLByA ; HL = HL / A, A = remainder push af inc b ld a, h or l jr nz, - ; Retrieve digits from stack - pop af or $30 ld (de), a inc de djnz - ; Terminate string with NULL xor a ld (de), a pop bc pop de ret
Comments
- This routine uses the common positive-integer radix conversion algorithm of repeatedly dividing a value by the desired radix (base case: the value is zero) and saving the remainders of each division.
- As this algorithm gives the digits in reverse order, they are pushed onto the hardware stack so that subsequently popping them yields the correct order.
- Note that the output string will not be fixed-width.
Example Usage
ld hl, -1004 ld de, OP1 call itoa ld hl, OP1 syscall PutS