Z80 Routines:Math:Advance Math
From WikiTI
Introduction
These are routines designed for math of a slightly higher level. These don't necessarily contribute to everyday coding, but might be useful for an OS that handles such math (or programming language).
nCr Algorithm
This computes "n choose r" using an algorithm that makes use of both shadow registers and other calls. This can very likely be optimised, so feel free to edit with a new version.
;=============================================================== nCrHL_DE: ;=============================================================== ;Inputs: ; hl is "n" ; de is "r" ;Outputs: ; interrupts off ; a is 0 ; bc is an intermediate result ; de is "n" ; hl is the result ; a' is not changed ; bc' is "r"+1 ; de' is the same as bc ; hl' is "r" or the compliment, whichever is smaller ;=============================================================== or a ;reset carry flag sbc hl,de ret c ;r should not be bigger than n sbc hl,de \ add hl,de jr nc,$+3 ex de,hl ;hl is R push de ld bc,1 ;A exx pop de ;N ld bc,1 ;C ld h,b \ ld l,c ;D nCrLoop: push de push hl call DE_Times_BC ;Returns BC unchanged, DEHL is the product push hl \ exx \ pop de push hl call DE_Div_BC ;Returns HL is the quotient, BC is not changed pop de push hl \ ex de,hl \ exx \ pop hl ld b,h \ ld c,l pop de \ add hl,de pop de \ inc de exx inc bc or a \ sbc hl,bc \ add hl,bc exx jr nc,nCrLoop ret
GCDHL_BC
This finds the greatest common divisor (GCD) of HL and BC.
GCDHL_BC: ;Inputs: ; HL is a number ; BC is a number ;Outputs: ; A is 0 ; BC is the GCD ; DE is 0 ;Destroys: ; HL ;Size: 25 bytes ;Speed: 30 to 49708 cycles ; -As slow as about 126 times per second at 6MHz ; -As fast as about 209715 times per second at 6MHz ;Speed break down: ; If HL=BC, 30 cycles ; 24+1552x ; If BC>HL, add 20 cycles ; *x is from 1 to at most 32 (because we use 2 16-bit numbers) ; or a \ sbc hl,bc ;B7ED42 19 ret z ;C8 5|11 add hl,bc ;09 11 jr nc,$+8 ;3006 11|31 ld a,h ;7C -- ld h,b ;60 -- ld b,a ;47 -- ld a,l ;7D -- ld l,c ;69 -- ld c,a ;4F -- Loop: call HL_Div_BC ;CD**** 1511 returns BC unchanged, DE is the remainder ld a,d \ or e ;7AB2 8 ret z ;C8 5|11 ld h,b \ ld l,c ;6069 8 ld b,d \ ld c,e ;424B 8 jr $-10 ;18F8 12
LCM
This is as simple as multiplying the two numbers and dividing by the GCD.
Credits and Contributions
- Zeda (Xeda) Elnara for the nCr and GCD algorithm